0,8x^2-4x-600=0

Solution for 0,8x^2-4x-600=0 equation:

0.8x^2-4x-600=0

a = 0.8; b = -4; c = -600;
Δ = b2-4ac
Δ = -42-4·0.8·(-600)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-44}{2*0.8}=\frac{-40}{1.6}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+44}{2*0.8}=\frac{48}{1.6}
=30
$